(1/x-5)^2-(x-5)^2

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Solution for (1/x-5)^2-(x-5)^2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/x-5)^2-(x-5)^2 = 0

(x^-1-5)^2-1*(x-5)^2 = 0

(x^-1-5)^2-1*(x-5)^2 = 0

10*x-x^2-10*x^-1+x^-2 = 0

10*x-x^2-10*x^-1+x^-2 = 0

x*(x^-3-x-10*x^-2+10) = 0

1*x^-3-1*x^1-10*x^-2+10*x^0 = 0

(10*x^3-1*x^4-10*x^1+1*x^0)/(x^3) = 0 // * x^6

x^3*(10*x^3-1*x^4-10*x^1+1*x^0) = 0

x^3

10*x^3-x^4-10*x+1 = 0

{ 1, -1 }

1

x = 1

10*x^3-x^4-10*x+1 = 0

1

x-1

9*x^2-x^3+9*x-1

10*x^3-x^4-10*x+1

x-1

x^4-x^3

9*x^3-10*x+1

9*x^2-9*x^3

9*x^2-10*x+1

9*x-9*x^2

1-x

x-1

0

9*x^2-x^3+9*x-1 = 0

{ 1, -1 }

1

x = 1

9*x^2-x^3+9*x-1 = 16

1

-1

x = -1

9*x^2-x^3+9*x-1 = 0

-1

x+1

10*x-x^2-1

9*x^2-x^3+9*x-1

x+1

x^3+x^2

10*x^2+9*x-1

-10*x^2-10*x

-x-1

x+1

0

10*x-x^2-1 = 0

DELTA = 10^2-(-1*(-1)*4)

DELTA = 96

DELTA > 0

x = (96^(1/2)-10)/(-1*2) or x = (-96^(1/2)-10)/(-1*2)

x = (4*6^(1/2)-10)/(-2) or x = (-4*6^(1/2)-10)/(-2)

x in { (4*6^(1/2)-10)/(-2), (-4*6^(1/2)-10)/(-2), 1, -1}

x*(x-((4*6^(1/2)-10)/(-2)))*(x-((-4*6^(1/2)-10)/(-2)))*(x-1)*(x+1) = 0

x*(x-((4*6^(1/2)-10)/(-2)))*(x-((-4*6^(1/2)-10)/(-2)))*(x-1)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-((-4*6^(1/2)-10)/(-2)) )

x-((-4*6^(1/2)-10)/(-2)) = 0 // + (-4*6^(1/2)-10)/(-2)

x = (-4*6^(1/2)-10)/(-2)

( x-((4*6^(1/2)-10)/(-2)) )

x-((4*6^(1/2)-10)/(-2)) = 0 // + (4*6^(1/2)-10)/(-2)

x = (4*6^(1/2)-10)/(-2)

( x-1 )

x-1 = 0 // + 1

x = 1

( x )

x = 0

x in { 0}

x in { -1, (-4*6^(1/2)-10)/(-2), (4*6^(1/2)-10)/(-2), 1 }

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